# Line slope calculator 2x+5y=35

**Straight line given by points A[5; 5] and B[10; 3]**

## Calculation:

**Slope-intercept form of line:**y = -0.4x+7

**Canonical form of the line equation:**2x+5y-35 = 0

**Parametric form of the line equation:**

x = 5t+5

y = -2t+5 ; t ∈ R

**Slope:**m = -0.4

**Slope angle of line: φ =**-21°48'5″ = -0.3805 rad

**X intercept:**x

_{0}= 17.5

**Y intercept:**y

_{0}= q = 7

**Distance line from the origin:**d

_{0}= 6.4993

**The length of the segment AB: |AB| =**5.3852

**Vector: AB =**(5; -2)

**Normal vector: n =**(2; 5)

**Midpoint of the segment AB: M =**[7.5; 4]

**Perpendicular Bisector equation:**5x-2y-29.5 = 0

**Vector OA = (5; 5) ; |OA| = 7.0711**

**Vector OB = (10; 3) ; |OB| = 10.4403**

**Scalar product OA .OB = 65**

**Angle ∠ AOB = 28°18'3″ = 0.4939 rad**