# Line slope calculator 7x+3y=38

**Straight line given by points A[2; 8] and B[5; 1]**

## Calculation:

**Slope-intercept form of line:**y = -2.3333x+12.6667

**Canonical form of the line equation:**7x+3y-38 = 0

**Parametric form of the line equation:**

x = 3t+2

y = -7t+8 ; t ∈ R

**Slope:**m = -2.3333

**Slope angle of line: φ =**-66°48'5″ = -1.1659 rad

**X intercept:**x

_{0}= 5.4286

**Y intercept:**y

_{0}= q = 12.6667

**Distance line from the origin:**d

_{0}= 4.9896

**The length of the segment AB: |AB| =**7.6158

**Vector: AB =**(3; -7)

**Normal vector: n =**(7; 3)

**Midpoint of the segment AB: M =**[3.5; 4.5]

**Perpendicular Bisector equation:**3x-7y+21 = 0

**Vector OA = (2; 8) ; |OA| = 8.2462**

**Vector OB = (5; 1) ; |OB| = 5.099**

**Scalar product OA .OB = 18**

**Angle ∠ AOB = 64°39'14″ = 1.1284 rad**