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Op-AMP vs Bridge Rectifier for VU meter

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So, I'm finally getting around to adding some toys to my system. One of them is this:


Closed VU.JPG

Open VU front.JPG


Bought it a long time ago for way too much money, but now I want to cannibalize it for the VU. I have noticed that the circuit that came with it included a quad op-amp. I don't care about accuracy, this is just eye candy, but I dont want it to cause feedback and what not. The interwebs have pointed me in two directions - one using the op-amp IC and the other using a simple diode rectifier with a resister and a cap. Obviously this is easier - but will it cause me problems for my simple project? My intention is to unsolder the VU meter from that circuit and wire it up internally - perhaps off the Audio Header on the motherboard.



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I'm not really clear on the specifics of your application but I can clarify the difference between an operational amplifier and a rectifier. At the bare minimum, they both operate on semiconductor junctions, though I'm sure you're already familiar with this. But that's where the similarities end. The op-amp does exactly what it suggests; it amplifies a small input signal to a larger one using a secondary (or auxiliary) input. They're packaged all fancy into an IC but underneath all the plastic, it's merely a common emitter transistor amplifier. Hence why it's a semiconductor system. The output will look exactly the same as the input, but amplified and inverted.


The bridge rectifier on the other hand produces a vastly different output. Your input (in this case an audio signal) after being processed by the rectifier will be exactly the same (with a loss of about 0.7v from the peak-peak voltage) but everything will be the absolute value of its counter part.


As you probably know, sound travels in waves and can be therefore be modelled by the humble sine function. Alterations in pitch are simply increasing/decreasing frequencies and changing volume is easily represented by the amplitude of the wave. An AC signal is also modelled by sine waves, and bridge rectifiers are the first simple piece of circuitry that mains power is passed through on its way to becoming a steady DC output. So as you can imagine, sound waves being passed through a bridge rectifier will simply be the same as what went in, but everything will be positive.


I said earlier that op-amps just amplify the input signal. Well, I kind of lied. Since they are also semiconductors at the core, they can also be used to rectify signals. The only difference is, they will rectify as a half wave rectifier would (i.e. Only the positive domain of the signal is preserved and the negative is clipped). In order to operate in this manner, the circuit will need to be biased towards either saturation or cut-off, but not completely. Just enough to clip the negative/positive domain of the input signal.


If you want the VU to react to changes in magnitude across both domains (i.e both the positive and negative), the transistor rectifier isn't of much use, since half the waveform will be scrapped. The bridge rectifier on the other hand will give you a both positive and negative domains as a single positive magnitude. The only problem you face with the rectifier is audio output signals are typically around 0.5V peak to peak. A diode requires about 0.7V (or 1.4V peak to peak) to even turn on! So the rectifier's useless as well. However, using the op amp, you can amplify the audio signal to a level that suits your VU.


You will need to determine what input voltage the VU meters need to be excited and work back from there. If they say require 0.25V to output a reading, that would mean an input signal requirement of 0.5V peak-peak. However the 0.5V only applies if the VU has a rectifier built in. If it doesn't, I'd assume it only operates on input magnitude (which is more likely). Ergo, you would only need an input voltage of 0.25V (say). To produce an output of this magnitude from the bridge rectifier, you will need to consider the operating voltage of the diodes 0.7V. Since a bridge rectifier has 4 diodes in total, only 2 of which are operating at any given point. They will take a toll of 1.4V from the input signal. Now since the output from the rectifier is rectified (duh) and the input is sinusoidal, you will need a 1.65V (i.e. 0.25V+1.4V) amplitude on the signal, or 3.3V peak-peak. If your audio output on the PC is only 0.5V peak-peak (again, I'm ball-parking values for convenience), the amplification will need to be 6.6V/V (math: 3.3V/0.5V). This is the gain you will need to produce with the op-amp and will depend on the IC you purchase. If it produces too much on the output, you could always use a voltage divider to fine tune it prior to rectification. Also, don't worry about the output being inverted, since it will be rectified anyway.


To help clarify this is how your circuit should be set up:


Input signal (PC output) -> op-amp -> rectifier -> VU

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